Physics · Ch 5 — Oscillations
Reference Circle Method
Reference Circle Method
Sections 5.4-5.6 built up the mathematics of linear S.H.M. from the differential equation onward. This section takes a completely different, purely GEOMETRIC route to the exact same equations, by relating linear S.H.M. to uniform circular motion (U.C.M.) -- a connection so useful that is called the "angular frequency" of an S.H.M. precisely because of it.
Picture a thin rod, pivoted at its centre, rotating uniformly in a vertical circle that lies in the x-y plane (Fig. 5.3). If this rod is illuminated from one side by a linear light source oriented parallel to the rod itself, its SHADOW falls on the y-axis. As the rod rotates around and around at constant angular speed, the tip of this shadow does NOT move at constant speed along the y-axis -- instead, it can be seen oscillating back and forth about the origin. The claim of this section is that this shadow motion is not merely "oscillation-like" -- it is EXACTLY a linear S.H.M., and working out its equations is a matter of straightforward geometry (projection) rather than solving a differential equation.
Set up the geometry precisely (Fig. 5.4): let a particle P perform anticlockwise uniform circular motion of radius r about a centre O, with angular velocity . Angular positions are measured from a fixed reference direction OX (so a particle at E, on OX itself, is at angular position zero; at F, 90 degrees further round, at angular position ; at G, 180 degrees round, at angular position ; and so on). Suppose at time t = 0 the particle is at some position , at reference angle from OX. By time t, it has swept out a further angle , so its total reference angle (the angle OP makes with OX) at time t is .
Choose a reference diameter -- say, the diameter FH lying along the y-axis -- and let M be the foot of the perpendicular dropped from P onto this diameter, so OM is the PROJECTION of the particle's position vector OP onto the chosen diameter. From the right-angled geometry, the length OM (call it y, the projected displacement) is
This is EXACTLY the equation of a linear S.H.M. of amplitude r (compare directly with Eq. 5.12, , with r playing the role of A). The angular velocity of the reference circular motion is thus revealed as exactly the same we have been calling the "angular frequency" of the S.H.M. -- the projection of the U.C.M.'s angular velocity becomes the S.H.M.'s angular frequency.
The same projection trick works for velocity and acceleration too. In the U.C.M., the particle's instantaneous (tangential) velocity has magnitude , directed tangent to the circle at P (Fig. 5.5); its projection onto the reference diameter works out (again by the right-angled geometry, now involving the angle between the tangential-velocity direction and the diameter) to
which matches exactly the S.H.M. velocity expression from section 5.5. Similarly, the U.C.M. particle's centripetal (radial) acceleration, of magnitude and always directed towards the centre O, projects onto the reference diameter as …
Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.
What this figure shows. A rigid rod pivoted at its centre, rotating uniformly in a VERTICAL circle that lies in the x-y plane, shown at some instant tilted at an angle to the axes. A linear light source, oriented parallel to the rod and placed to one side, illuminates the rod so that its shadow falls on the y-axis (drawn as a vertical line to one side of the rotating rod). Dashed projection lines are drawn from each end of the rod straight across (parallel to the x-axis, i.e. the direction of illumination) to the y-axis, showing exactly where the shadow of the rod's tip lands at that instant. The figure establishes the physical set-up -- illumination direction parallel to x, shadow observed along y -- that …
Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.
What this figure shows. A circle of radius r centred at the origin O, with a particle P performing anticlockwise uniform circular motion on it. The reference direction OX (positive x-axis) is marked, from which all angular positions are measured: a labelled point E on the circle lies on OX itself (angular position zero), point F is 90 degrees anticlockwise from E (on the positive y-axis), point G is 180 degrees from E (on the negative x-axis). The particle's position at time t = 0 is marked P0, at reference angle phi from OX; by time t it has swept through a further angle omegat to reach its current position P, so the position vector OP makes angle (omegat + phi) with OX. The reference diameter FH (lying along the y-axis) is drawn, and a perpendicular dashed line is dropped from P onto this diameter, landing at point M -- so OM is the PROJECTION of OP onto the y-axis, shown …
Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.
What this figure shows. The same circle of radius r, centre O, with particle P performing anticlockwise uniform circular motion, shown at the same general angular position (omegat + phi) from OX as in Fig. 5.4. At P, the particle's instantaneous (tangential) velocity vector of magnitude romega is drawn TANGENT to the circle at P, perpendicular to the radius OP, pointing in the sense of the anticlockwise rotation. A dashed perpendicular projection line is dropped from the TIP of this velocity vector onto the reference diameter (the y-axis), showing the component v_y = romegacos(omega*t+phi) -- the projection of the tangential velocity onto the reference diameter -- which the tex …