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Exercise Problems · Q3

Q.Find the bandwidth and gain at 3dB line for an amplifier having mid-band gain of 600 having 3dB frequencies 100Hz and 300kHz.

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[!TLDR]

Bandwidth is the span between the 3 dB frequencies (299.9 kHz), and the gain there is 0.707×0.707 \times the mid-band gain (424.2).

The lower and upper 3 dB frequencies (fLf_L and fHf_H) are the half-power points of the frequency response: at each, the voltage gain has dropped to 1/2=0.7071/\sqrt{2} = 0.707 of its maximum (mid-band) value, so the power is halved (3 dB down). The amplifier's useful bandwidth is the frequency range between them.

Given: mid-band gain Am=600A_m = 600, fL=100 Hzf_L = 100\,\text{Hz}, fH=300 kHzf_H = 300\,\text{kHz}.

Step 1 — bandwidth:

BW=fH−fL=300 kHz−100 Hz=299900 Hz=299.9 kHzBW = f_H - f_L = 300\,\text{kHz} - 100\,\text{Hz} = 299900\,\text{Hz} = 299.9\,\text{kHz}

Step 2 — gain at the 3 dB line:

A3dB=0.707×Am=0.707×600=424.2A_{3\text{dB}} = 0.707 \times A_m = 0.707 \times 600 = 424.2

[!ANSWER]

Bandwidth =299.9 kHz= 299.9\,\text{kHz}; gain at the 3 dB line =424.2= 424.2.

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