Q.CE amplifier circuit using Silicon transistor is shown in figure. Calculate i) $A_v$ ii) $A_i$ iii) $A_p$. Given $I_E$ = 1.32mA and $\beta$ =100

In the $r_e'$ model of a CE amplifier the voltage gain is $A_v = Z_0/r_e'$ (where $Z_0 = R_C \parallel R_L$), the current gain is $A_i = \beta$, and the power gain is $A_p = A_i \times A_v$. We first find $r_e'$ from the given emitter current. …

[!TLDR]

Use the $r_e'$ model of the CE amplifier: $A_v = Z_0/r_e' = 253.86$, $A_i = \beta = 100$, and $A_p = A_i A_v = 25386$.

A common emitter amplifier gives both voltage and current amplification. In its AC ($r_e'$) model the transistor's emitter diode is replaced by the AC resistance $r_e'$ and the collector behaves as a current source, so the small-signal parameters become simple ratios of resistances.

Given: silicon transistor, $I_E = 1.32\,\text{mA}$, $\beta = 100$, $R_C = 10\,\text{k}\Omega$, $R_L = 10\,\text{k}\Omega$.

Step 1 — AC resistance of the emitter diode (silicon):

Step 2 — output impedance (collector load seen by the signal): …