Skip to content
MISCELLANEOUS EXERCISE 6 (II) · Q161

Q.Let f:R−{2}→Rf:R-\{2\}\to R be defined by f(x)=x2−4x−2f(x)=\dfrac{x^2-4}{x-2} and g:R→Rg:R\to R be defined by g(x)=x+2g(x)=x+2. Examine whether f=gf=g or not.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
77% · 161/210 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

f(x)=x2−4x−2=(x−2)(x+2)x−2=x+2f(x)=\dfrac{x^2-4}{x-2}=\dfrac{(x-2)(x+2)}{x-2}=x+2, valid only for x≠2x\ne2 (domain R−{2}R-\{2\}, since the original expression is undefined at x=2x=2).

g(x)=x+2g(x)=x+2 for all x∈Rx\in R (domain RR). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.