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MISCELLANEOUS EXERCISE 6 (II) · Q184

Q.If a2=b3=c4=d5a^2=b^3=c^4=d^5, show that log⁡abcd=4730\log_a bcd=\dfrac{47}{30}.

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Let a2=b3=c4=d5=ta^2=b^3=c^4=d^5=t. Then a=t1/2, b=t1/3, c=t1/4, d=t1/5a=t^{1/2},\ b=t^{1/3},\ c=t^{1/4},\ d=t^{1/5}.

log⁡abcd=log⁡ab+log⁡ac+log⁡ad\log_abcd=\log_ab+\log_ac+\log_ad.

log⁡ab=log⁡blog⁡a=(1/3)log⁡t(1/2)log⁡t=1/31/2=23\log_ab=\dfrac{\log b}{\log a}=\dfrac{(1/3)\log t}{(1/2)\log t}=\dfrac{1/3}{1/2}=\dfrac23.

log⁡ac=(1/4)log⁡t(1/2)log⁡t=1/41/2=12\log_ac=\dfrac{(1/4)\log t}{(1/2)\log t}=\dfrac{1/4}{1/2}=\dfrac12. …

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