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MISCELLANEOUS EXERCISE 6 (II) · Q180

Q.Find value of 3+log⁡103432+12log⁡10(494)+12log⁡10(125)\dfrac{3+\log_{10}343}{2+\dfrac12\log_{10}\left(\dfrac{49}{4}\right)+\dfrac12\log_{10}\left(\dfrac{1}{25}\right)}.

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Numerator: 3+log⁡10343=3+log⁡1073=3+3log⁡107=3(1+log⁡107)3+\log_{10}343=3+\log_{10}7^3=3+3\log_{10}7=3(1+\log_{10}7).

Denominator: 2+12log⁡10494+12log⁡10125=2+12[log⁡1049−log⁡104]+12[0−log⁡1025]2+\dfrac12\log_{10}\dfrac{49}{4}+\dfrac12\log_{10}\dfrac{1}{25}=2+\dfrac12\left[\log_{10}49-\log_{10}4\right]+\dfrac12\left[0-\log_{10}25\right]

=2+12[2log⁡107−2log⁡102]−12[2log⁡105]=2+log⁡107−log⁡102−log⁡105=2+\dfrac12[2\log_{10}7-2\log_{10}2]-\dfrac12[2\log_{10}5]=2+\log_{10}7-\log_{10}2-\log_{10}5 …

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