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MISCELLANEOUS EXERCISE 6 (II) · Q170

Q.If log⁡(a+b2)=12(log⁡a+log⁡b)\log\left(\dfrac{a+b}{2}\right)=\dfrac12(\log a+\log b), then show that a=ba=b.

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log⁡(a+b2)=12(log⁡a+log⁡b)=12log⁡(ab)=log⁡ab\log\left(\dfrac{a+b}{2}\right)=\dfrac12(\log a+\log b)=\dfrac12\log(ab)=\log\sqrt{ab}.

Since log⁡\log is one-one, a+b2=ab\dfrac{a+b}{2}=\sqrt{ab}. …

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