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MISCELLANEOUS EXERCISE 6 (II) · Q143

Q.Find whether the following function is one-one: f:R→Rf:R\to R defined by f(x)=x2+5f(x)=x^2+5.

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f(x)=x2+5f(x)=x^2+5. f(1)=1+5=6f(1)=1+5=6 and f(−1)=1+5=6f(-1)=1+5=6. Since f(1)=f(−1)f(1)=f(-1) but 1≠−11\ne-1, ff is not one-one. …

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