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MISCELLANEOUS EXERCISE 6 (II) · Q144

Q.Find whether the following function is one-one: f:R−{3}→Rf:R-\{3\}\to R defined by f(x)=5x+7x−3f(x)=\dfrac{5x+7}{x-3} for x∈R−{3}x\in R-\{3\}.

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f(x)=5x+7x−3f(x)=\dfrac{5x+7}{x-3} on R−{3}R-\{3\}. Suppose f(x1)=f(x2)f(x_1)=f(x_2):

5x1+7x1−3=5x2+7x2−3  ⟹  (5x1+7)(x2−3)=(5x2+7)(x1−3)\dfrac{5x_1+7}{x_1-3}=\dfrac{5x_2+7}{x_2-3} \implies (5x_1+7)(x_2-3)=(5x_2+7)(x_1-3)

5x1x2−15x1+7x2−21=5x1x2−15x2+7x1−215x_1x_2-15x_1+7x_2-21=5x_1x_2-15x_2+7x_1-21 …

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