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MISCELLANEOUS EXERCISE 6 (I) · Q137

Q.If f(x)=2x2+bx+cf(x)=2x^2+bx+c and f(0)=3f(0)=3 and f(2)=1f(2)=1, then f(1)f(1) is equal to (A) −2-2 (B) 00 (C) 11 (D) 22

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f(x)=2x2+bx+cf(x)=2x^2+bx+c. f(0)=c=3f(0)=c=3.

f(2)=8+2b+3=1  ⟹  2b=1−11=−10  ⟹  b=−5f(2)=8+2b+3=1 \implies 2b=1-11=-10 \implies b=-5. …

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