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MISCELLANEOUS EXERCISE 6 (II) · Q163

Q.Let f:R→Rf:R\to R be given by f(x)=x3+1f(x)=x^3+1 for all x∈Rx\in R. Draw its graph.

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f(x)=x3+1f(x)=x^3+1 is the standard cubic y=x3y=x^3 shifted up by 11 unit.

Key points: at x=−1x=-1, y=(−1)3+1=0y=(-1)^3+1=0, giving (−1,0)(-1,0); at x=0x=0, y=1y=1, giving (0,1)(0,1); at x=1x=1, y=1+1=2y=1+1=2, giving (1,2)(1,2). The curve has the familiar S-shape of x3x^3 — flat-ish near its inflection point (0,1)(0,1), rising steeply for ∣x∣|x| large, s …

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