Skip to content
MISCELLANEOUS EXERCISE 6 (II) · Q166

Q.Show that, log⁡∣x2+1+x∣+log⁡∣x2+1−x∣=0\log\left|\sqrt{x^2+1}+x\right|+\log\left|\sqrt{x^2+1}-x\right|=0.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
79% · 166/210 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Consider the product (x2+1+x)(x2+1−x)=(x2+1)−x2=1\left(\sqrt{x^2+1}+x\right)\left(\sqrt{x^2+1}-x\right)=\left(x^2+1\right)-x^2=1 (difference of squares).

Taking log⁡\log of both sides: log⁡[(x2+1+x)(x2+1−x)]=log⁡1=0\log\left[\left(\sqrt{x^2+1}+x\right)\left(\sqrt{x^2+1}-x\right)\right]=\log1=0. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.