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Exercise 3.2 · Q28

Q.Find the Cartesian co-ordinates of the point whose polar co-ordinates are (12,7π3)\left(\dfrac{1}{2}, \dfrac{7\pi}{3}\right)

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7π3=2π+π3\dfrac{7\pi}{3}=2\pi+\dfrac{\pi}{3}, so cos⁡7π3=cos⁡π3=12\cos\dfrac{7\pi}{3}=\cos\dfrac{\pi}{3}=\dfrac12 and sin⁡7π3=sin⁡π3=32\sin\dfrac{7\pi}{3}=\sin\dfrac{\pi}{3}=\dfrac{\sqrt3}{2}. x=12×12=14x=\dfrac12\times\dfrac12=\dfrac14. $y=\dfrac12\times\d …

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