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Exercise 3.2 · Q42

Q.In △ABC\triangle ABC, if a=18a = 18, b=24b = 24, c=30c = 30 then find the value of cos⁡A2\cos\dfrac{A}{2}.

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s=36s=36, s−a=18s-a=18. $\cos\dfrac A2=\sqrt{\dfrac{s(s-a)}{bc}}=\sqrt{\dfrac{36\times18}{24\times30}}=\sqrt{\dfrac{648}{720}}=\sqrt{\dfrac{9}{10}}=\dfrac{3} …

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