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Exercise 3.2 · Q44

Q.In △ABC\triangle ABC, if a=18a = 18, b=24b = 24, c=30c = 30 then find the value of A(△ABC)A(\triangle ABC).

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A(△ABC)=s(s−a)(s−b)(s−c)=36×18×12×6=46656=216A(\triangle ABC)=\sqrt{s(s-a)(s-b)(s-c)}=\sqrt{36\times18\times12\times6}=\sqrt{46656}=216. (Cross-check: since 18,24,3018,24,30 is a right triangle with legs 18,2418,24, the area is also directly $\frac12\tim …

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