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Exercise 3.2 · Q45

Q.In △ABC\triangle ABC, if a=18a = 18, b=24b = 24, c=30c = 30 then find the value of sin⁡A\sin A.

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sin⁡A=2sin⁡A2cos⁡A2=2×110×310=610=35\sin A=2\sin\dfrac A2\cos\dfrac A2=2\times\dfrac{1}{\sqrt{10}}\times\dfrac{3}{\sqrt{10}}=\dfrac{6}{10}=\dfrac35. (Cross-check: since this is a 3-4-5-type right triangle scaled by 6, the angle opposi …

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