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Exercise 3.2 · Q41

Q.In △ABC\triangle ABC, if a=18a = 18, b=24b = 24, c=30c = 30 then find the value of sin⁡A2\sin\dfrac{A}{2}.

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s=18+24+302=36s=\dfrac{18+24+30}{2}=36; s−b=12s-b=12, s−c=6s-c=6. $\sin\dfrac A2=\sqrt{\dfrac{(s-b)(s-c)}{bc}}=\sqrt{\dfrac{12\times6}{24\times30}}=\sqrt{\dfrac{72}{720}}=\sqrt{\dfrac{1}{10}} …

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