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Worked Examples · Example 5.1

Q.Describe the state of oscillation if the phase angle is 1110°.

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✓ Free question

1110° = 3(360°) + 30°; the leftover 30° gives x = A sin 30° = A/2, in the 4th oscillation moving to +extreme.

1110∘=3×360∘+30∘1110^\circ = 3\times 360^\circ + 30^\circ

The three full turns mean three completed oscillations, so the particle is in its 4th oscillation. The leftover phase 30° gives

x=Asin⁡30∘=A2x = A\sin 30^\circ = \frac{A}{2}

and since the phase is increasing through the first quadrant, the particle is at +A/2 moving toward the positive extreme.

✓Final answer

1110° = 3×360° + 30° → during its 4th oscillation the particle is at +A/2 and moving toward the positive extreme.

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