Skip to content
Question 64 of 82

Q.If the particle starts its motion from mean position, the phase difference between displacement and acceleration is ____.

(a) 2π2\pi rad
(b) π/2\pi/2 rad
(c) π\pi rad
(d) π/4\pi/4 rad
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2018MCQ· 1mImportance★★★★★
78% · 64/82 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

In SHM, a=−ω2xa = -\omega^2 x, so acceleration and displacement are always antiparallel — a phase difference of π\pi radians, regardless of the starting point of the motion.

For a particle performing linear SHM starting from the mean position, displacement is x=Asin⁡(ωt)x = A\sin(\omega t). Its acceleration is a=d2xdt2=−Aω2sin⁡(ωt)=−ω2xa = \dfrac{d^2x}{dt^2} = -A\omega^2\sin(\omega t) = -\omega^2 x.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.