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Worked Examples · Example 5.1

Q.The total energy of a particle of mass 200 g, performing S.H.M. is 10⁻² J. Find its maximum velocity and period if the amplitude is 7 cm.

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v_max = √(2E/m) = √(2×10⁻²/0.2) = 0.3162 m/s; T = 2πA/v_max = 1.391 s.

Maximum velocity. The total energy equals the maximum kinetic energy:

E=12mvmax2⇒vmax=2Em=2×10−20.2=0.3162 m/sE = \tfrac{1}{2}m v_{max}^2 \Rightarrow v_{max} = \sqrt{\frac{2E}{m}} = \sqrt{\frac{2\times10^{-2}}{0.2}} = 0.3162\ \mathrm{m/s} …

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