Skip to content
Question 71 of 82

Q.A simple pendulum of length 1 m has mass 10 g and oscillates freely with amplitude of 5 cm. Calculate its potential energy at extreme position.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2020Subjective· 3mImportance★★★★★
87% · 71/82 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

At the extreme, all the total SHM energy (½mω²A²) is potential.

For the pendulum, ω=g/L=9.8/1=3.13\omega = \sqrt{g/L} = \sqrt{9.8/1} = 3.13 rad/s, so ω2=9.8 s−2\omega^2 = 9.8\ \text{s}^{-2}.

At the extreme position, the entire mechanical energy is potential:

PEmax=12mω2A2=12(0.01)(9.8)(0.05)2PE_{max} = \frac{1}{2}m\omega^2A^2 = \frac{1}{2}(0.01)(9.8)(0.05)^2 …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.