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Question Bank (3 marks) · Q2

Q.Draw the ac equivalent circuit of op-amp.

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[!TLDR]

The ac model: input resistance RiR_i across the inputs, and a dependent source AVdA V_d in series with output resistance RoR_o.

For small-signal (ac) analysis the op-amp is represented by three elements. Across the two input terminals is the differential input resistance RiR_i, which draws the (very small) input current. The amplifying action is modelled by a dependent voltage source of value AVdA V_d, where AA is the open-loop gain and Vd=V2−V1V_d = V_2 - V_1 is the voltage between the non-inverting and inverting inputs. This source is in series with the output resistance RoR_o, from which the output VoV_o is taken. On no load, Vo=AVdV_o = A V_d; under load, RoR_o causes a small drop. In the ideal op-amp Ri→∞R_i \to \infty, Ro→0R_o \to 0 and A→∞A \to \infty.

[!ANSWER]

Input resistance RiR_i across the inputs; dependent source AVdA V_d (Vd=V2−V1V_d = V_2 - V_1) in series with RoR_o at the output, so Vo=AVdV_o = A V_d (no load).

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