Skip to content
Solved Examples · Example 6

Q.Find the output of the following circuit :

Karnataka PUCTextbookNumericImportance★★★★★est
31% · 31/100 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →
Figure — A three-op-amp network. \(A_1\) is an inverting amplifier: input \(1\text{ V}\) through \(2\text{ k}\Omega\), feedback \(4\text{ — Class 12 Electronics question
FigureA three-op-amp network. \(A_1\) is an inverting amplifier: input \(1\text{ V}\) through \(2\text{ k}\Omega\), feedback \(4\text{ — Class 12 Electronics question

[!TLDR]

With VO1=−2 VV_{O1}=-2\text{ V} from the inverting stage and VO2=6 VV_{O2}=6\text{ V} from the non-inverting stage, the subtractor output is VO=4 VV_O=4\text{ V}.

The signal passes through three op-amp stages, each analysed with its own standard relation.

Stage A1A_1 (inverting amplifier):

VO1=−RfRiVi=−4k2k×1=−2 VV_{O1}=-\dfrac{R_f}{R_i}V_i=-\dfrac{4\text{k}}{2\text{k}}\times1=-2\text{ V}

Stage A2A_2 (non-inverting amplifier):

VO2=(1+RfRi)Vi=(1+6k3k)×2=3×2=6 VV_{O2}=\left(1+\dfrac{R_f}{R_i}\right)V_i=\left(1+\dfrac{6\text{k}}{3\text{k}}\right)\times2=3\times2=6\text{ V}

Stage A3A_3 (subtractor), which combines the two stage outputs: …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.