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Solved Examples · Example 1

Q.If common mode gain and differential mode gain for a differential amplifier are 0.1 & 500 respectively, find CMRR in dB.

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[!TLDR]

With Ad=500A_d=500 and AC=0.1A_C=0.1, the CMRR is 5000, which is about 74 dB.

The common mode rejection ratio (CMRR) tells how well a differential amplifier amplifies the wanted difference signal while rejecting the unwanted common-mode signal (such as noise picked up equally by both inputs). A large CMRR is desirable because it means the amplifier strongly favours the differential signal over the common-mode one. It is defined as

CMRR=AdAC\text{CMRR}=\dfrac{A_d}{A_C}

and, because the ratio is usually very large, it is quoted in decibels:

CMRR (in dB)=20log⁡10AdAC\text{CMRR (in dB)}=20\log_{10}\dfrac{A_d}{A_C}

Substituting the given differential-mode gain Ad=500A_d=500 and common-mode gain AC=0.1A_C=0.1:

CMRR=5000.1=5000\text{CMRR}=\dfrac{500}{0.1}=5000

CMRR (in dB)=20log⁡105000=20×3.699=74 dB\text{CMRR (in dB)}=20\log_{10}5000=20\times3.699=74\text{ dB}

[!ANSWER]

CMRR =5000=5000; CMRR (in dB) =74 dB=74\text{ dB}.

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