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Exercise Problems · Q4

Q.Determine VdcV_{dc} and IdcI_{dc} of SCR HWR. Given firing angle is 30∘^\circ and rms voltage of ac input to the rectifier is 30 V and load is 10 Ω\Omega.

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[!TLDR]

With Vm=2×30=42.43V_m = \sqrt{2}\times 30 = 42.43 V, the half-wave-rectifier formula gives Vdc=12.59V_{dc} = 12.59 V and Idc=1.259I_{dc} = 1.259 A.

For an SCR half-wave rectifier the average load voltage over the full cycle is Vdc=Vm2π(1+cos⁡α)V_{dc} = \frac{V_m}{2\pi}(1+\cos\alpha) and Idc=Vdc/RI_{dc} = V_{dc}/R.

Given α=30∘\alpha = 30^\circ, Vrms=30V_{rms} = 30 V and R=10 ΩR = 10\ \Omega:

Vm=2×30=42.43 VV_m = \sqrt{2}\times 30 = 42.43\ \text{V} …

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