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5.1 · Q14

Q.Obtain the new equation of the locus xy − 2x − 2y + 4 = 0 if the origin is shifted to the point O'(2, 2), the direction of axes remaining the same.

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Substitute x=X+2x=X+2, y=Y+2y=Y+2 into xy−2x−2y+4=0xy-2x-2y+4=0:

(X+2)(Y+2)−2(X+2)−2(Y+2)+4=0.(X+2)(Y+2)-2(X+2)-2(Y+2)+4=0.

Expand (X+2)(Y+2)=XY+2X+2Y+4(X+2)(Y+2)=XY+2X+2Y+4. So the equation becomes …

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