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5.3 · Q58

Q.N(3,−4) is the foot of the perpendicular drawn from the origin to line L. Find the equation of line L.

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If N(x0,y0)=(3,−4)N(x_0,y_0)=(3,-4) is the foot of the perpendicular from the origin to line LL, then LL is perpendicular to ONON and passes through NN. Slope of ON=−43ON=\dfrac{-4}{3}, so slope of L=34L=\dfrac34. Through N(3,−4)N(3,-4): y+4=34(x−3)⇒4y+16=3x−9⇒3x−4y−25=0y+4=\dfrac34(x-3) \Rightarrow 4y+16=3x-9 \Rightarrow 3x-4y-25=0. (Equivalently, usi …

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