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5.2 · Q26

Q.Find the value of k for which points P(k,−1), Q(2,1) and R(4,5) are collinear.

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For P(k,−1)P(k,-1), Q(2,1)Q(2,1), R(4,5)R(4,5) to be collinear, slope PQPQ = slope QRQR. Slope QR=5−14−2=2QR=\dfrac{5-1}{4-2}=2. Slope PQ=1−(−1)2−k=22−kPQ=\dfrac{1-(-1)}{2-k}=\dfrac{2}{2-k}. Setting equal: …

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