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Misc-II · Q115

Q.The vertices of a triangle are A(1,4), B(2,3) and C(1,6). Find the equations of the medians of ∆ABC.

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A(1,4)A(1,4), B(2,3)B(2,3), C(1,6)C(1,6). Midpoint BC=(1.5,4.5)BC=(1.5,4.5); median from AA: slope =4.5−41.5−1=1=\dfrac{4.5-4}{1.5-1}=1, so y−4=1(x−1)⇒x−y+3=0y-4=1(x-1) \Rightarrow x-y+3=0. Midpoint CA=(1,5)CA=(1,5); median from BB: slope =5−31−2=−2=\dfrac{5-3}{1-2}=-2, so y−3=−2(x−2)⇒2x+y−7=0y-3=-2(x-2) \Rightarrow 2x+y-7=0. Midpoint AB=(1.5,3.5)AB=(1.5,3.5); median from CC: slope $=\dfra …

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