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Misc-I · Q92

Q.If kx+2y−1=0 and 6x−4y+2=0 are identical lines, then determine k. (A) −3 (B) −1/3 (C) 1/3 (D) 3

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For kx+2y−1=0kx+2y-1=0 and 6x−4y+2=06x-4y+2=0 to be identical, k6=2−4=−12\dfrac{k}{6}=\dfrac{2}{-4}=\dfrac{-1}{2}. Since 2−4=−12\dfrac{2}{-4}=-\dfrac12, this matches the constant-term ratio, confirming consistency. T …

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