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5.1 · Q15

Q.Obtain the new equation of the locus y² − 4x − 4y + 12 = 0 if the origin is shifted to the point O'(2, 2), the direction of axes remaining the same.

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Substitute x=X+2x=X+2, y=Y+2y=Y+2 into y2−4x−4y+12=0y^2-4x-4y+12=0:

(Y+2)2−4(X+2)−4(Y+2)+12=0.(Y+2)^2-4(X+2)-4(Y+2)+12=0. …

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