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5.2 · Q24

Q.Without using Pythagoras theorem show that points A(4,4), B(3, 5) and C(−1, −1) are the vertices of a right angled triangle.

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For A(4,4)A(4,4), B(3,5)B(3,5), C(−1,−1)C(-1,-1): slope AB=5−43−4=1−1=−1AB=\dfrac{5-4}{3-4}=\dfrac{1}{-1}=-1. Slope AC=−1−4−1−4=−5−5=1AC=\dfrac{-1-4}{-1-4}=\dfrac{-5}{-5}=1. Slope BC=−1−5−1−3=−6−4=32BC=\dfrac{-1-5}{-1-3}=\dfrac{-6}{-4}=\dfrac32. …

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