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5.4 · Q71

Q.Find the co-ordinates of the orthocenter of the triangle whose vertices are A(3,−2), B(7,6), C(−1,2).

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Vertices A(3,−2)A(3,-2), B(7,6)B(7,6), C(−1,2)C(-1,2). Altitude from A⊥BCA\perp BC: slope BC=2−6−1−7=12BC=\dfrac{2-6}{-1-7}=\dfrac12, altitude slope =−2=-2: y+2=−2(x−3)⇒2x+y−4=0y+2=-2(x-3) \Rightarrow 2x+y-4=0 ...(i). Altitude from B⊥ACB\perp AC: slope AC=2+2−1−3=−1AC=\dfrac{2+2}{-1-3}=-1, altitude slope =1=1: y−6=x−7⇒x−y−1=0y-6=x-7 \Rightarrow x-y-1=0 ...(ii). From (ii), $y …

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