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5.3 · Q49

Q.The vertices of a triangle are A(3,4), B(2,0) and C(−1,6). Find the equation of the line containing the mid points of sides AB and BC.

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Midpoint of ABAB (A(3,4), B(2,0)) is (52,2)\left(\dfrac52,2\right). Midpoint of BCBC (B(2,0), C(−1,6)) is (12,3)\left(\dfrac12,3\right). Slope between them: 3−20.5−2.5=1−2=−12\dfrac{3-2}{0.5-2.5}=\dfrac{1}{-2}=-\dfrac12. Through (52,2)\left(\dfrac52,2\right): $y-2=-\dfrac12\left(x-\dfrac …

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