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Misc-II · Q117

Q.The vertices of a triangle are A(1,4), B(2,3) and C(1,6). Find the equations of the altitudes of ∆ABC.

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A(1,4)A(1,4), B(2,3)B(2,3), C(1,6)C(1,6). Altitude from A⊥BCA\perp BC (slope BC =−3=-3, so altitude slope =1/3=1/3): y−4=13(x−1)⇒x−3y+11=0y-4=\dfrac13(x-1) \Rightarrow x-3y+11=0. Altitude from B⊥CAB\perp CA (CA is vertical, so its perpendicular is horizontal): y=3y=3. Altitude from C⊥ABC\perp AB (slope AB =−1=-1, so a …

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