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Misc-II · Q126

Q.Find the equations of the diagonals of the rectangle whose sides are contained in the lines x=8, x=10, y=11 and y=12.

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The rectangle's sides x=8,x=10,y=11,y=12x=8,x=10,y=11,y=12 give corners (8,11),(10,11),(10,12),(8,12)(8,11),(10,11),(10,12),(8,12). Diagonal 1 joins (8,11)(8,11) and (10,12)(10,12): slope =1/2=1/2, so y−11=12(x−8)⇒x−2y+14=0y-11=\dfrac12(x-8) \Rightarrow x-2y+14=0. Diagonal 2 joins (10,11)(10,11) and (8,12)(8,12): slope $=\dfrac{12-11}{8-10}= …

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