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Misc-II · Q119

Q.Find the equation of the line which passes through the point of intersection of lines x + y + 9 = 0, 2x + 3y + 1 = 0 and which makes X-intercept 1.

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The required line has the form (x+y+9)+k(2x+3y+1)=0(x+y+9)+k(2x+3y+1)=0, i.e. (1+2k)x+(1+3k)y+(9+k)=0(1+2k)x+(1+3k)y+(9+k)=0. Its X-intercept is −9+k1+2k-\dfrac{9+k}{1+2k}; setting this to 11: −(9+k)=1+2k⇒−9−k=1+2k⇒−10=3k⇒k=−103-(9+k)=1+2k \Rightarrow -9-k=1+2k \Rightarrow -10=3k \Rightarrow k=-\dfrac{10}{3}. Substituting back: coefficient of xx: 1+2(−10/3)=−17/31+2(-10/3)=-17/3; coefficient of yy: 1+3(−10/3)=−91+3(-10/3)=-9; constant …

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