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Question 101 of 106

Q.(a) Calculate spin only magnetic moment of M2+^{2+} ion. [atomic number of M = 26]

(b) Write condensed electronic configuration of Gadolinium [Z = 64].
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 3mImportance★★★★★
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Fe2+^{2+} (d6d^6) has 4 unpaired electrons: μ=24≈4.90\mu=\sqrt{24}\approx4.90 BM. Gd (Z=64): [Xe]4f75d16s2[Xe]4f^75d^16s^2.

(a) Spin-only magnetic moment of M2+M^{2+}, atomic number of M = 26 (iron, Fe):

Fe is [Ar]3d64s2[Ar]3d^64s^2. Fe2+Fe^{2+} loses the two 4s4s electrons, giving [Ar]3d6[Ar]3d^6.

Distributing 6 electrons over 5 degenerate dd orbitals by Hund's rule: each of the 5 orbitals gets one electron first (5 singly occupied), then the 6th electron must pair up in one orbital — leaving 4 unpaired electrons.

μ=n(n+2)\mu = \sqrt{n(n+2)} BM =4×6=24≈4.90= \sqrt{4\times6} = \sqrt{24} \approx 4.90 BM

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