Skip to content

Physics · Ch 10 — Magnetic Fields due to Electric Current

Straight Wire

10.5.1

Straight Wire

Consider a straight wire of length LL (Fig. 10.8), carrying a steady current II, placed in an external magnetic field B⃗\vec{B} applied perpendicular to the wire. Let v⃗d\vec{v}_d be the (common) drift velocity of the conduction electrons inside the wire. In a time tt, the total charge qq that flows across any cross-section of the wire is, by the definition of current, q=Itq=It; and since the electrons travel with drift speed vdv_d, this same charge can also be related to the length of wire the electrons traverse in that time, giving

q=ILvdq = \frac{IL}{v_d}

(using t=L/vdt=L/v_d, the time for an electron to drift the full length LL of the segment). Now apply the single-charge Lorentz force law (Section 10.2) to this "lumped" charge qq, treated as moving with the drift velocity vdv_d through the field BB:

Fm=qvdBsin⁡(90∘)=(ILvd)vdB(1)=ILB,F_m = qv_dB\sin(90^\circ) = \left(\frac{IL}{v_d}\right)v_dB(1) = ILB,

where the 90∘90^\circ reflects the given condition that BB is applied perpendicular to the wire, and the two factors of vdv_d conveniently cancel -- the DRIFT SPEED itself drops out of the final formula entirely, leaving the force expressed purely in terms of the macroscopic, directly-measurable current II. This is therefore the magnetic force on a straight segment of wire, of length LL, carrying current II, in a field BB applied exactly perpendicular to the wire:

Fm=ILB.F_m = ILB.

More generally, if B⃗\vec{B} is NOT necessarily perpendicular to the wire, the same derivation (carried through with the general angle θ\theta between the current direction and B⃗\vec{B}) gives the fully vectorial version of this force law. Defining a length vector L⃗\vec{L} directed ALONG the wire, in the sense of the current flow, with magnitude equal to the wire's length:

F⃗m=IL⃗×B⃗.\vec{F}_m = I\vec{L}\times\vec{B}. …

Figure 10.8Fig. 10.8: Electrons in a wire experiencing a magnetic force
Fig. 10.8 — Fig. 10.8: Electrons in a wire experiencing a magnetic force

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. A straight segment of current-carrying wire of length L is shown with its conduction electrons drifting with drift velocity v⃗d\vec{v}_d (drawn opposite to the direction of conventional current flow, since electrons are negatively charged). An external uniform magnetic field B⃗\vec{B} is applied perpendicular to the wire, with its field lines drawn coming OUT of the plane of the paper (dots along the length of the wire). A resultant force arrow F⃗m\vec{F}_m is drawn pointing UPWARD on the wire (perpendicular to both the wire and to B), illustrating that the sideways push experienced by the individual drifting electrons adds up, over the whole segment, to a single net sideways force on the wire it …