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Exercise Problems · Q11

Q.The frequency of the phase shift oscillator is 125 Hz125\,\text{Hz}. If the value of capacitance of the capacitor used is 0.22 μF0.22\,\mu\text{F}, calculate the value of resistance used.

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[!TLDR]

Solving f=12π6 RCf = \dfrac{1}{2\pi\sqrt{6}\,RC} for RR with f=125 Hzf = 125\,\text{Hz}, C=0.22 μFC = 0.22\,\mu\text{F} gives R≈2363.9 ΩR \approx 2363.9\,\Omega.

The RC phase shift oscillator frequency is f=12π6 RCf = \dfrac{1}{2\pi\sqrt{6}\,RC}, rearranged for the resistor as

R=12π6 C f.R = \frac{1}{2\pi\sqrt{6}\,C\,f}.

Step 1 — substitute: R=12π6×0.22×10−6×125R = \dfrac{1}{2\pi\sqrt{6}\times0.22\times10^{-6}\times125}. …

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