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Exercise Problems · Q13

Q.The RC network of Wein bridge oscillator consists of resistors and capacitors of values R1=R2=R=270 kΩR_1 = R_2 = R = 270\,k\Omega and C1=C2=C=470 pFC_1 = C_2 = C = 470\,\text{pF}. Determine the frequency of oscillations.

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[!TLDR]

Substituting R=270 kΩR = 270\,k\Omega and C=470 pFC = 470\,\text{pF} into f=12πRCf = \dfrac{1}{2\pi RC} gives f≈1254.8 Hzf \approx 1254.8\,\text{Hz}.

The Wein bridge oscillator with equal arms oscillates at f=12πRCf = \dfrac{1}{2\pi RC}.

Step 1 — form the RCRC product: RC=(270×103)(470×10−12)=1.269×10−4 sRC = (270\times10^{3})(470\times10^{-12}) = 1.269\times10^{-4}\,\text{s}. …

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