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Solved Examples · Example 5

Q.A transistor Colpitts oscillator has L=10 mHL = 10\,\text{mH}, C1=0.1 μFC_1 = 0.1\,\mu\text{F} and C2=0.1 μFC_2 = 0.1\,\mu\text{F}. Determine the frequency of oscillation.

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[!TLDR]

The series capacitors give Ceq=0.05 μFC_{eq} = 0.05\,\mu\text{F}, which with L=10 mHL = 10\,\text{mH} gives f≈7.116 kHzf \approx 7.116\,\text{kHz}.

In a Colpitts oscillator the tank capacitor is the series combination of C1C_1 and C2C_2 (their junction is grounded, so they appear in series across the inductor). The equivalent capacitance is

Ceq=C1C2C1+C2,C_{eq} = \frac{C_1 C_2}{C_1 + C_2},

and the frequency is the tank resonance f=12πL Ceqf = \dfrac{1}{2\pi\sqrt{L\,C_{eq}}}. …

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