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Question Bank (3 marks) · Q3

Q.With a circuit diagram, explain the principle of lead lag network.

Karnataka PUCTextbookLong· 3mImportance★★★★★est
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[!TLDR]

A lead–lag network (series R1C1 + shunt R2C2) passes maximum output with zero phase shift only at f=1/(2πRC)f = 1/(2\pi RC); below it the output leads (lead network) and above it it lags (lag network).

A lead–lag network is a circuit in which the output voltage may either lead or lag the input voltage depending on frequency. As shown in Figure 6.3.3, it consists of a series combination of R1R_1 and C1C_1 followed by a parallel combination of R2R_2 and C2C_2; the input ViV_i is applied at the left and the output VoV_o is taken across the R2∥C2R_2\parallel C_2 branch.

At low frequencies the series capacitor C1C_1 offers a very high reactance and behaves like an open circuit, so almost no signal reaches the output; the small output leads the input, so the circuit behaves as a lead network. At high frequencies the shunt capacitor C2C_2 offers a very low reactance and behaves like a short circuit, so it bypasses the output to the return line; the small output lags the input, so the circuit behaves as a lag network.

At one particular frequency ff the output voltage is maximum. If R1=R2=RR_1 = R_2 = R and C1=C2=CC_1 = C_2 = C, this frequency is

f=12πRCf = \frac{1}{2\pi RC}

At this frequency the phase angle between output and input is zero. Thus the phase angle is positive (lead) below ff, negative (lag) above ff, and zero at ff. This zero-phase, maximum-output property makes the lead–lag network the frequency-selective feedback element of the Wein bridge oscillator.

[!ANSWER]

The series C1C_1 blocks low frequencies and the shunt C2C_2 shorts high frequencies, so the output is maximum only at f=1/(2πRC)f = 1/(2\pi RC) (equal components), where the phase angle is zero; below ff the output leads and above ff it lags — hence the name lead–lag network.

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