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Question Bank (3 marks) · Q2

Q.With a circuit diagram, explain the principle of phase shift in RC circuit.

Karnataka PUCTextbookLong· 3mImportance★★★★★est
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[!TLDR]

An RC section makes its output (across R) lead the input by an angle ϕ\phi with tan⁡ϕ=1/(ωCR)\tan\phi = 1/(\omega C R); three 60∘60^\circ sections give the required 180∘180^\circ.

A phase-shift circuit is basically an RC network. Consider one section (Figure 6.3.1a): the input voltage ViV_i is applied through a series capacitor C, and the output VoV_o is taken across the resistor R connected from the junction to the return line.

Because the same current flows through C and R, and the current in a capacitor leads the voltage across it, the voltage developed across R (which is in phase with the current) leads the applied voltage ViV_i by an angle ϕ\phi. From the phasor relation of the series RC section,

tan⁡ϕ=XCR=1ωCR\tan\phi = \frac{X_C}{R} = \frac{1}{\omega C R}

The value of ϕ\phi depends on R and C. If R=0R = 0, VoV_o leads ViV_i by 90∘90^\circ; if R=∞R = \infty, ϕ=0∘\phi = 0^\circ. In practice R is varied to a value that makes each section produce a lead of 60∘60^\circ.

When three such identical RC sections are cascaded, the total phase shift becomes 3×60∘=180∘3 \times 60^\circ = 180^\circ; i.e. the network output leads its input by 180∘180^\circ. An inverting amplifier adds a further 180∘180^\circ, giving 360∘360^\circ around the loop, which is exactly the phase condition needed for oscillation. This is the principle used in the RC phase-shift oscillator.

[!ANSWER]

The voltage across R leads the input because capacitor current leads its voltage, the lead being tan⁡ϕ=1/(ωCR)\tan\phi = 1/(\omega C R). R is set so each RC section gives 60∘60^\circ, and three sections together produce the 180∘180^\circ phase shift required for phase-shift oscillation.

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