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Solved Examples · Example 8

Q.A RC phase shift oscillator has R1=R2=R3=R=10 kΩR_1 = R_2 = R_3 = R = 10\,k\Omega and C1=C2=C3=C=0.047 μFC_1 = C_2 = C_3 = C = 0.047\,\mu\text{F}. Determine the frequency of oscillation.

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[!TLDR]

Substituting R=10 kΩR = 10\,k\Omega and C=0.047 μFC = 0.047\,\mu\text{F} into f=12π6 RCf = \dfrac{1}{2\pi\sqrt{6}\,RC} gives f≈138.3 Hzf \approx 138.3\,\text{Hz}.

The RC phase shift oscillator is an RC-type oscillator used for low (audio) frequencies. Its feedback network is three cascaded RC sections, each contributing 60∘60^\circ so the network gives the 180∘180^\circ needed with the inverting amplifier. The frequency at which the total phase shift is exactly 180∘180^\circ is

f=12π6 RC.f = \frac{1}{2\pi\sqrt{6}\,RC}. …

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