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Solved Examples · Example 10

Q.The frequency of the phase shift oscillator is 78 Hz78\,\text{Hz}. If the value of capacitance of the capacitor used is 220 nF220\,\text{nF}. Calculate the value of resistance of the resistor.

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[!TLDR]

Solving f=12π6 RCf = \dfrac{1}{2\pi\sqrt{6}\,RC} for RR with f=78 Hzf = 78\,\text{Hz}, C=220 nFC = 220\,\text{nF} gives R≈3.785 kΩR \approx 3.785\,k\Omega.

The RC phase shift oscillator frequency is f=12π6 RCf = \dfrac{1}{2\pi\sqrt{6}\,RC}. Rearranging for the resistor,

R=12π6 C f.R = \frac{1}{2\pi\sqrt{6}\,C\,f}.

Step 1 — substitute: R=12π6×78×220×10−9R = \dfrac{1}{2\pi\sqrt{6}\times78\times220\times10^{-9}}. …

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