Numericals · Q16
Q.A circular coil of wire is made up of 100 turns, each of radius 8.0 cm. If a current of 0.40 A passes through it, what will be the magnetic field at the centre of the coil?
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Start your 14-day free trial to unlock the full solution →For turns, the centre-of-loop formula generalises to . Substituting , A, m, T.m/A: $B=\dfrac{(4\pi\times10^{-7})(100)(0.40)}{2(0.08)}=\dfr …
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