Skip to content
Questions 3-23 · Q5

Q.Draw graphs of displacement, velocity and acceleration against phase angle, for a particle performing linear S.H.M. from

(a) the mean position
(b) the positive extreme position. Deduce your conclusions from the graph.
Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
49% · 40/82 Questions
✓ Free question

(a) Starting from the mean position (ϕ=0\phi=0): x=Asin⁡ωtx=A\sin\omega t (sine curve: 0 at t=0, +A at T/4, 0 at T/2, -A at 3T/4, 0 at T), v=Aωcos⁡ωtv=A\omega\cos\omega t (cosine curve: +Aω+A\omega at t=0, 0 at T/4, −Aω-A\omega at T/2, 0 at 3T/4, +Aω+A\omega at T), a=−Aω2sin⁡ωta=-A\omega^2\sin\omega t (inverted-sine curve: 0 at t=0, −Aω2-A\omega^2 at T/4, 0 at T/2, +Aω2+A\omega^2 at 3T/4, 0 at T) -- see Fig. 5.6. (b) Starting from the positive extreme (ϕ=π/2\phi=\pi/2): x=Acos⁡ωtx=A\cos\omega t (cosine curve), v=−Aωsin⁡ωtv=-A\omega\sin\omega t (inverted-sine curve), a=−Aω2cos⁡ωta=-A\omega^2\cos\omega t (inverted-cosine curve) -- see Fig. 5.7; each curve here is simply the corresponding curve of case (a), shifted by a quarter period. Conclusions drawn from comparing the graphs: (1) x, v and a are all periodic functions of time, each of period T; (2) the displacement-time and acceleration-time curves are always of the same ('sine') type, while the velocity-time curve is of the other ('cosine') type; (3) there is a phase difference of π/2\pi/2 radian between displacement and velocity; (4) there is a phase difference of π/2\pi/2 radian between velocity and acceleration; (5) there is a phase difference of π\pi radian between displacement and acceleration (i.e. they are always of opposite sign, consistent with a=−ω2xa=-\omega^2x); and the shapes of all curves repeat after a phase of 2π2\pi, i.e. after time T. [!ANSWER] Graphs as described; the five conclusions listed above.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.