Q.Draw graphs of displacement, velocity and acceleration against phase angle, for a particle performing linear S.H.M. from
(a) Starting from the mean position (): (sine curve: 0 at t=0, +A at T/4, 0 at T/2, -A at 3T/4, 0 at T), (cosine curve: at t=0, 0 at T/4, at T/2, 0 at 3T/4, at T), (inverted-sine curve: 0 at t=0, at T/4, 0 at T/2, at 3T/4, 0 at T) -- see Fig. 5.6. (b) Starting from the positive extreme (): (cosine curve), (inverted-sine curve), (inverted-cosine curve) -- see Fig. 5.7; each curve here is simply the corresponding curve of case (a), shifted by a quarter period. Conclusions drawn from comparing the graphs: (1) x, v and a are all periodic functions of time, each of period T; (2) the displacement-time and acceleration-time curves are always of the same ('sine') type, while the velocity-time curve is of the other ('cosine') type; (3) there is a phase difference of radian between displacement and velocity; (4) there is a phase difference of radian between velocity and acceleration; (5) there is a phase difference of radian between displacement and acceleration (i.e. they are always of opposite sign, consistent with ); and the shapes of all curves repeat after a phase of , i.e. after time T. [!ANSWER] Graphs as described; the five conclusions listed above.
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