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Questions 3-23 · Q18

Q.The period of oscillation of a body of mass m1 suspended from a light spring is T. When a body of mass m2 is tied to the first body and the system is made to oscillate, the period is 2T. Compare the masses m1 and m2.

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The period of mass m1m_1 alone on the spring is T=2πm1/kT=2\pi\sqrt{m_1/k}. With m2m_2 tied on as well, the period becomes 2T=2π(m1+m2)/k2T=2\pi\sqrt{(m_1+m_2)/k}. Dividing the two period expressions (k cancels), $$\frac{2T}{T}=\sqrt{\frac{m_1+m_2}{m_1}}\Rightarrow2=\sqrt{\frac{m_1+m_2}{m_1}}\Rightarrow4=\frac{m_1+m_2}{m_1}\Righ …

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