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Questions 3-23 · Q9

Q.In SI units, the differential equation of an S.H.M. is d2xdt2=−36x\frac{d^2x}{dt^2}=-36x. Find its frequency and period.

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The given differential equation is d2xdt2=−36x\frac{d^2x}{dt^2}=-36x, i.e. d2xdt2+36x=0\frac{d^2x}{dt^2}+36x=0. Comparing with the standard S.H.M. form d2xdt2+ω2x=0\frac{d^2x}{dt^2}+\omega^2x=0 (Eq. 5.5), we identify ω2=36\omega^2=36, so ω=6\omega=6 rad/s. The frequency is n=ω2π=62π=66.2832≈0.9549n=\frac{\omega}{2\pi}=\frac{6}{2\pi}=\frac{6}{6.2832}\approx0.9549 Hz (matching the printed 0.9548 H …

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